Difference between revisions of "Calculus:Limits"

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But If a = 1 then you will get  
But If a = 1 then you will get  


<math> ({1^2-1 \over 1-1})^2 = {0 \over 0}</math>
<math> ({1^2-1 \over 1-1})^2 = ({0 \over 0})^2</math>


But denominator can't be 0 so this equation is undifind
But denominator can't be 0 so this equation is undifind

Revision as of 12:14, 29 August 2021

When you see this equation it means you are try to let x approaches a.

You may have a question why can't we just write it as

some times we can't tell what is the F(a) equals to.

example 1

Screen Shot 2021-08-28 at 8.02.52 PM.png

But If a = 1 then you will get

But denominator can't be 0 so this equation is undifind