Difference between revisions of "Solve Differential Equation by means of Separating Variables"

From PKC
Jump to navigation Jump to search
Line 4: Line 4:
<math> y^2 * dy = x^2 * dx</math>
<math> y^2 * dy = x^2 * dx</math>


<math>{\int y^2 * dy }={ \int x^2 * dx}</math>
<math>{\int y^2 * dy } = { \int x^2 * dx}</math>
 
<math>{\int y^2 * dy } = { y^3 \over 3}</math>
 
<math>{ \int x^2 * dx} = { x^3 \over 3}</math>
 
But one side of the equation needs to add a constant c.
 
<math>{ y^3 \over 3} = { x^3 \over 3} + c</math>
 
<math> y^3  = x^3  + 3c</math>
 
constant times 3 will still be constant so 3c-> c.
 
<math> \sqrt[3] {y^3}.  = \sqrt[3] {x^3  + c}</math>

Revision as of 14:00, 28 September 2021

Examples

Ex1

But one side of the equation needs to add a constant c.

constant times 3 will still be constant so 3c-> c.