Difference between revisions of "Math equation demo"
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<math>P_{wave} = \frac{\rho g^2 h^2 T_e}{6400 \pi} </math> | <math>P_{wave} = \frac{\rho g^2 h^2 T_e}{6400 \pi} </math> | ||
<math>\frac{\vec{X}_0}{P(\vec{X}_0)} \nabla_{\{H,T,B,\eta \}} P (\vec{X}_0) = (2, 1, 1, 1) </math> | |||
In more explicit terms, the equaliser consists of an object ''E'' and a morphism ''eq'' : ''E'' → ''X'' satisfying <math>f \circ eq = g \circ eq</math>, | In more explicit terms, the equaliser consists of an object ''E'' and a morphism ''eq'' : ''E'' → ''X'' satisfying <math>f \circ eq = g \circ eq</math>, | ||
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The following equation shows how to use square root: | |||
<math> c = \sqrt{a^2 + b^2} </math> | |||
A morphism <math>m:O \rightarrow X</math> is said to '''equalise''' <math>f</math> and <math>g</math> if <math>f \circ m = g \circ m</math>. | A morphism <math>m:O \rightarrow X</math> is said to '''equalise''' <math>f</math> and <math>g</math> if <math>f \circ m = g \circ m</math>. | ||
Latest revision as of 09:01, 10 January 2022
The following shows an angled degree symbol:
In more explicit terms, the equaliser consists of an object E and a morphism eq : E → X satisfying , and such that, given any object O and morphism m : O → X, if , then there exists a unique morphism u : O → E such that .
The following equation shows how to use square root:
A morphism is said to equalise and if .
