Revision as of 11:25, 24 July 2021

Calculus

This is a course that Henry and Ben are studying during 2021.

$(x^{n})'=n*x^{n-1}$

$(f+g)'=f'+g'$

$(f-g)'=f'-g'$

$(f*g)'=f*g'+g*f'$

${(f \over g)'}=(gf'-fg')/g^{2}$

@@ Line 13: / Line 13: @@
 <math>(f*g)'=f*g'+ g*f'</math>
 #The Quotient Rule
-<math>(f \over g)' =(gf'-fg')/g^2</math>
+<math>{(f \over g)'} =(gf'-fg')/g^2</math>
 ==Integration==