Revision as of 11:29, 24 July 2021

Calculus

This is a course that Henry and Ben are studying during 2021.

$(x^{n})'=n*x^{n-1}$

$(f+g)'=f'+g'$

$(f-g)'=f'-g'$

$(f*g)'=f*g'+g*f'$

$({f \over g})'={(gf'-fg') \over g^{2}}$

@@ Line 14: / Line 14: @@
 #The Quotient Rule
+<math>({f \over g})' = {(gf'-fg') \over g^2} </math>
 ====Derivative of Trigonometric Functions====
-<math>({f \over g})' = {(gf'-fg') \over g^2} </math>
 ==Integration==