Difference between revisions of "Inverse"

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The notion of [[wikipedia:Inverse function|inverse]] in mathematical operation is simply the anti-operator.
The notion of [[wikipedia:Inverse function|inverse]] in mathematical operation is simply the [[anti-operator]]. Note that it is different from [[reverse]], where it can just be used to mean the order of presentation being reversed.


=Excerpt from Wikipedia=
=Excerpt from Wikipedia=
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===Compositional inverseInverses and composition===
===Compositional inverseInverses and composition===


If {{mvar|f}} is an invertible function with domain {{mvar|X}} and codomain {{mvar|Y}}, then
If <math>f</math> is an invertible function with domain <math>X</math> and codomain <math>Y</math>, then


: <math> f^{-1}\left( \, f(x) \, \right) = x</math>, for every <math>x \in X</math>; and <math> f\left( \, f^{-1}(y) \, \right) = y</math>, for every <math>y \in Y. </math>.<ref name=":2" />
: <math> f^{-1}\left( \, f(x) \, \right) = x</math>, for every <math>x \in X</math>; and <math> f\left( \, f^{-1}(y) \, \right) = y</math>, for every <math>y \in Y. </math>.


Using the [[composition of functions]], we can rewrite this statement as follows:
Using the [[wikipedia:Function composition|composition of functions]], we can rewrite this statement as follows:


: <math> f^{-1} \circ f = \operatorname{id}_X</math> and <math>f \circ f^{-1} = \operatorname{id}_Y, </math>
: <math> f^{-1} \circ f = \operatorname{id}_X</math> and <math>f \circ f^{-1} = \operatorname{id}_Y, </math>


where {{math|id<sub>''X''</sub>}} is the [[identity function]] on the set {{mvar|X}}; that is, the function that leaves its argument unchanged. In [[category theory]], this statement is used as the definition of an inverse [[morphism]].
where <math>\operatorname{id}_X</math> is the [[wikipedia:Identity function|identity function]] on the set <math>X</math>; that is, the function that leaves its argument unchanged. In [[Category Theory]], this statement is used as the definition of an inverse [[wikipedia:morphism|morphism]].


Considering function composition helps to understand the notation {{math|''f''<sup> −1</sup>}}. Repeatedly composing a function with itself is called [[iterated function|iteration]]. If {{mvar|f}} is applied {{mvar|n}} times, starting with the value {{mvar|x}}, then this is written as {{math|''f''<sup> ''n''</sup>(''x'')}}; so {{math|''f''<sup> 2</sup>(''x'') {{=}} ''f'' (''f'' (''x''))}}, etc. Since {{math|''f''<sup> −1</sup>(''f'' (''x'')) {{=}} ''x''}}, composing {{math|''f''<sup> −1</sup>}} and {{math|''f''<sup> ''n''</sup>}} yields {{math|''f''<sup> ''n''−1</sup>}}, "undoing" the effect of one application of {{mvar|f}}.
==Related Pages==
*[[Definition::Anti-operator]]

Latest revision as of 08:30, 19 August 2021

The notion of inverse in mathematical operation is simply the anti-operator. Note that it is different from reverse, where it can just be used to mean the order of presentation being reversed.

Excerpt from Wikipedia

The following paragraph is copied from Wikipedia.

Compositional inverseInverses and composition

If is an invertible function with domain and codomain , then

, for every ; and , for every .

Using the composition of functions, we can rewrite this statement as follows:

and

where is the identity function on the set ; that is, the function that leaves its argument unchanged. In Category Theory, this statement is used as the definition of an inverse morphism.

Related Pages