Difference between revisions of "Calculus:Derivative of Polynomial Functions"
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<math> f'(x) = {{(4x^5 - x^3 + 5x)}{(16x^3 - 2x + 10)}-(4x^4 - x^2 + 10x){(20x^4 - 3x^2 + 5)} \over {(16x^8-8x^6+80x^5+x^4-20x^3+100x^2)}} </math> | <math> f'(x) = {{(4x^5 - x^3 + 5x)}{(16x^3 - 2x + 10)}-(4x^4 - x^2 + 10x){(20x^4 - 3x^2 + 5)} \over {(16x^8-8x^6+80x^5+x^4-20x^3+100x^2)}} </math> | ||
<math> f'(x) = {{(4x^5 - x^3 + 5x)}{(16x^3 - 2x + 10)}-(4x^4 - x^2 + 10x){(20x^4 - 3x^2 + 5)} \over {(16x^8-8x^6+80x^5+x^4-20x^3+100x^2)}} </math> | |||
<math>f'(x) ={ {(64x^8 - 24x^6 + 40x^5 + 82x^4 - 10x^3 - 10x^2 + 50x) - (80x^8 - 32x^6 + 200x^5 + 23x^4 - 30x^3 - 5x^2 + 50x)} \over {(16x^8-8x^6+80x^5+x^4-20x^3+100x^2)}} | |||
</noinclude> | </noinclude> |
Revision as of 14:04, 24 August 2021
Derivative of Polynomial Functions
=Newton Derivative of Polynomial Functions=
- The sum rule
- The Difference Rule
- The Product Rule
- The Quotient Rule
=Leibniz Derivative of Polynomial Functions=
- The sum rule
- The Difference Rule
- The Product Rule
- The Quotient Rule
Examples
Example 1
Ex1:
Using the sum rule we can divided in to different part
so we will started to work on different part by using power rule.
Example 2
Ex2:
The Product Rule
Using the Product Rule we can divided in to different part
Example 3
Ex3:
The Quotient Rule
<math>f'(x) ={ {(64x^8 - 24x^6 + 40x^5 + 82x^4 - 10x^3 - 10x^2 + 50x) - (80x^8 - 32x^6 + 200x^5 + 23x^4 - 30x^3 - 5x^2 + 50x)} \over {(16x^8-8x^6+80x^5+x^4-20x^3+100x^2)}}