Difference between revisions of "Calculus:Limits"
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But If a = 1 then you will get | But If a = 1 then you will get | ||
<math> {1^2-1 \over 1-1} = {0 \over 0}</math> | |||
<math> ({1^2-1 \over 1-1})^2 = {0 \over 0}</math> | |||
But denominator can't be 0 so this equation is undifind |