Difference between revisions of "Solve Differential Equation by means of Separating Variables"

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==Examples==
==Examples==
Ex1 <math> {dx \over dy} = {x^2 \over y^2}</math>
Ex1 <math> {dy \over dx} = {x^2 \over y^2}</math>


<math> y^2 * dy = x^2 * dx</math>
<math> y^2 * dy = x^2 * dx</math>
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<math> \sqrt[3] {y^3}.  = \sqrt[3] {x^3  + c}</math>
<math> \sqrt[3] {y^3}.  = \sqrt[3] {x^3  + c}</math>
Ex2 y' = xy
<math> {dy \over dx} = xy</math>
<math> dy = xy * dx</math>
<math> {dy \over y} = x * dx}</math>
<math>\int {1 \over y} dy = \int x * dx}</math>
==reference==
https://www.youtube.com/watch?v=C7nuJcJriWM&list=PLEjLk3Wl8akWPgisw-u9jrmdN67dgPibe&index=33

Revision as of 14:05, 28 September 2021

Examples

Ex1

But one side of the equation needs to add a constant c.

constant times 3 will still be constant so 3c-> c.


Ex2 y' = xy

Failed to parse (syntax error): {\displaystyle {dy \over y} = x * dx}}

Failed to parse (syntax error): {\displaystyle \int {1 \over y} dy = \int x * dx}}

reference

https://www.youtube.com/watch?v=C7nuJcJriWM&list=PLEjLk3Wl8akWPgisw-u9jrmdN67dgPibe&index=33