Difference between revisions of "Calculus:Limits"

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# Sum Rule: The limit of the sum of two functions is the sum of their limits : <math>\lim_{x \to c} (f(x)+g(x)) = \lim_{x \to c} (f(x)) + \lim_{x \to c} (g(x))</math>
# Sum Rule: The limit of the sum of two functions is the sum of their limits : <math>\lim_{x \to c} (f(x)+g(x)) = \lim_{x \to c} (f(x)) + \lim_{x \to c} (g(x))</math>
# Difference Rule: The limit of the difference of two functions is the difference of their limits : <math>\lim_{x \to c} (f(x) - g(x)) = \lim_{x \to c} f(x) -\lim_{x \to c} g(x)</math>
# Difference Rule: The limit of the difference of two functions is the difference of their limits : <math>\lim_{x \to c} (f(x) - g(x)) = \lim_{x \to c} f(x) -\lim_{x \to c} g(x)</math>
# Product Rule: The limit of a product of two functions is the product of their limits :  <math>\lim_{x \to c} (f(x) * g(x)) = \lim_{x \to c} f(x) * \lim_{x \to c} g(x)</math>

Revision as of 08:27, 23 November 2021

When you see this equation it means you are trying to let "x" approach "a".

You may have a question, "why can't we just write it as ?"

Sometimes we can't tell what F(a) equals.

example 1

Screen Shot 2021-08-28 at 8.02.52 PM.png

But if a = 1 then you will get

Denominator can't be 0 so it is undefined at that point.

But in the graph if a = 1 it looks like it is than f(x) = 4

So the logic of the limit is approaching to not equal to. (what's the difference?)

it will be like this:

When we say x=1 then x is one.

But if we say then it could be 1.00000....0001 or 9.9999....999, x will not be 1 it will just be close to one.

When looking at the graph, you will see h equals Δx. Δx means the rate of change of x. Most of the time we will like h or Δx approaches to 0.

Properties of Limits

  1. Sum Rule: The limit of the sum of two functions is the sum of their limits :
  2. Difference Rule: The limit of the difference of two functions is the difference of their limits :
  3. Product Rule: The limit of a product of two functions is the product of their limits :