Difference between revisions of "Calculus:Limits"
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# Sum Rule: The limit of the sum of two functions is the sum of their limits : <math>\lim_{x \to c} (f(x)+g(x)) = \lim_{x \to c} (f(x)) + \lim_{x \to c} (g(x))</math> | # Sum Rule: The limit of the sum of two functions is the sum of their limits : <math>\lim_{x \to c} (f(x)+g(x)) = \lim_{x \to c} (f(x)) + \lim_{x \to c} (g(x))</math> | ||
# Difference Rule: The limit of the difference of two functions is the difference of their limits : <math>\lim_{x \to c} (f(x) - g(x)) = \lim_{x \to c} f(x) -\lim_{x \to c} g(x)</math> | # Difference Rule: The limit of the difference of two functions is the difference of their limits : <math>\lim_{x \to c} (f(x) - g(x)) = \lim_{x \to c} f(x) -\lim_{x \to c} g(x)</math> | ||
# Product Rule: The limit of a product of two functions is the product of their limits : <math>\lim_{x \to c} (f(x) * g(x)) = \lim_{x \to c} f(x) * \lim_{x \to c} g(x)</math> |
Revision as of 08:27, 23 November 2021
When you see this equation it means you are trying to let "x" approach "a".
You may have a question, "why can't we just write it as ?"
Sometimes we can't tell what F(a) equals.
example 1
But if a = 1 then you will get
Denominator can't be 0 so it is undefined at that point.
But in the graph if a = 1 it looks like it is than f(x) = 4
So the logic of the limit is approaching to not equal to. (what's the difference?)
it will be like this:
When we say x=1 then x is one.
But if we say then it could be 1.00000....0001 or 9.9999....999, x will not be 1 it will just be close to one.
When looking at the graph, you will see h equals Δx. Δx means the rate of change of x. Most of the time we will like h or Δx approaches to 0.
Properties of Limits
- Sum Rule: The limit of the sum of two functions is the sum of their limits :
- Difference Rule: The limit of the difference of two functions is the difference of their limits :
- Product Rule: The limit of a product of two functions is the product of their limits :